left double bracket x plus 2y equals negative 1 negative x minus 3y equals negative 2

Answer 1

To solve this system of equations:

First, let's rearrange the equations to solve for x:

1) x + 2y = -1 (Equation 1)
2) -x - 3y = -2 (Equation 2)

From Equation 1, we can isolate x by subtracting 2y from both sides:
x = -1 - 2y

Now, substitute this value of x into Equation 2:

-(-1 - 2y) - 3y = -2
1 + 2y - 3y = -2
- y = -2 - 1
- y = -3

Now, substitute the value of y back into Equation 1 to solve for x:

x + 2(-3) = -1
x - 6 = -1
x = -1 + 6
x = 5

Therefore, the solution to the system of equations is:
x = 5
y = -3