LeBron’s average bowling score for the season is 180 with a standard deviation of 28. Use technology to determine which of the following represents the probability that LeBron records a score higher than 200

Question

A. 17%
B. 23.8%
C. 1.1%
D. 76.2%

Answer 1

To calculate the probability that LeBron records a score higher than 200, we can use a Z-score calculation.

Z = (X - μ) / σ
Z = (200 - 180) / 28
Z = 0.7143

Using a Z-table or calculator, we can find that the probability of a Z-score of 0.7143 or higher is approximately 23.8%. Therefore, the correct answer is B. 23.8%.

Answer 2

is this right

Answer 3

I apologize for the mistake in my previous response. Let me correct it.

To calculate the probability that LeBron records a score higher than 200, we need to first convert 200 to a Z-score using the formula:

Z = (X - μ) / σ
Z = (200 - 180) / 28
Z = 0.7143

Next, we look up the probability corresponding to a Z-score of 0.7143 in a standard normal distribution table or by using a calculator.

The probability of a Z-score of 0.7143 or higher is approximately 23.8%. Therefore, the correct answer is B. 23.8%.