by inspection, the numerator is (x^2-25)(x-3)
The denominator is (x-5)(x-6)(x-8)
so, there is a hole at x=5, but zeros at x = -5 and x=3
vertical asymptotes at x=6,8
hor asymp at y=1
Leave any unneeded answer spaces blank.
[Hint: use synthetic division to solve.]
f(x) = (1x^3 - 3x^2 - 25x + 75)/(1x^3 - 19x^2 + 118x - 240)
the roots of f(x), in increasing order is/are.... ___, ___, ___
f(x) has holes when x is... ___, ___, ___
f(x)has vertical asymptotes when x is....___, ___, ___
f(x) has a horizontal asymptote at y = ___
1 answer
1 answer