Layla launches a toy rocket from a platform. The height of the rocket in feet is given by h, equals, minus, 16, t, squared, plus, 136, t, plus, 72h=−16t

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+136t+72 where tt represents the time in seconds after launch. How many seconds have gone by when the rocket is at its highest point?

1 answer

To find the time when the rocket is at its highest point, we need to find the vertex of the parabolic function h(t) = -16t^2 + 136t + 72.

The time of the vertex is given by the formula t = -b/2a, where a = -16 and b = 136 in the function h(t).

Plugging in the values, we get t = -136 / (2*(-16)) = -136 / (-32) = 4.25 seconds.

Therefore, the rocket is at its highest point 4.25 seconds after launch.