Asked by Anonymous
Latent heat question:
Your car's windshield is covered with a .58 cm thick layer of ice. The ice has an area of 1.6m^2. If the temperature of the ice is -2C, how much heat is required to melt all the ice?
Your car's windshield is covered with a .58 cm thick layer of ice. The ice has an area of 1.6m^2. If the temperature of the ice is -2C, how much heat is required to melt all the ice?
Answers
Answered by
bobpursley
heatrequired=massice*specificheatice*(0-(-2))+ massice*latentheat
ok, massice= densityice*volumeice. I would use the density of ice about .932g/cm^2, Volume ice= .58cm*1.6m^2*10^4cm^2/m^2
and you have to look up the specific heat of ice, it is about half that of water, as I recall. Look it up.
ok, massice= densityice*volumeice. I would use the density of ice about .932g/cm^2, Volume ice= .58cm*1.6m^2*10^4cm^2/m^2
and you have to look up the specific heat of ice, it is about half that of water, as I recall. Look it up.
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