Last week, Ellen bought 4 apples for $2.40. this week she bought 9 apples for $5.40. if the cost per apple remains the same, how many apples could she buy next week

Answer 1

To find out how many apples Ellen could buy next week, we first need to determine the cost per apple based on her purchases last week and this week.

Last week's purchase: Ellen bought 4 apples for $2.40.

Cost per apple last week: \[ \text{Cost per apple} = \frac{\text{Total cost}}{\text{Number of apples}} = \frac{2.40}{4} = 0.60 \text{ dollars per apple} \]

This week's purchase: Ellen bought 9 apples for $5.40.

Cost per apple this week: \[ \text{Cost per apple} = \frac{5.40}{9} = 0.60 \text{ dollars per apple} \]

Both calculations confirm that the cost per apple is consistent at $0.60.

Now, let's denote the amount of money Ellen plans to spend next week as \( x \). The number of apples she could buy next week, based on the same cost per apple, would be: \[ \text{Number of apples} = \frac{x}{0.60} \]

Without a specific amount \( x \) given for next week’s spending, we cannot determine the exact number of apples she could buy.

If you provide how much money she will spend next week, I can calculate the exact number of apples. Alternatively, if you wanted a general expression, it is \[ \text{Number of apples} = \frac{x}{0.60} \] where \( x \) is Ellen's budget for next week.

Answer 2

answer choice

1 apple for $1.20

6 apples for $3.40

10 apples for $6.00

13 apples for $8.20

Answer 3

To determine how many apples Ellen could buy next week based on the given choices and the established cost per apple of $0.60, we can calculate how many apples correspond to each of the provided amounts.

1. 1 apple for $1.20: This is not correct because $1.20 is greater than $0.60. \[ \text{Number of apples} = \frac{1.20}{0.60} = 2 \text{ apples} \]

2. 6 apples for $3.40: \[ \text{Number of apples} = \frac{3.40}{0.60} \approx 5.67 \text{ apples} \]

3. 10 apples for $6.00: \[ \text{Number of apples} = \frac{6.00}{0.60} = 10 \text{ apples} \] This is correct since $6.00 exactly matches the cost of buying 10 apples at $0.60 each.

4. 13 apples for $8.20: \[ \text{Number of apples} = \frac{8.20}{0.60} \approx 13.67 \text{ apples} \]

Out of the provided options, only the choice "10 apples for $6.00" is valid because it corresponds to the cost of $0.60 per apple.

So, Ellen could buy 10 apples for $6.00 next week.