Asked by Amy~
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An average person expends ~100 kj to walk 1km. How far will the average car travel by the time it expends the same amount of energy (i.e. 100 kJ) as a person who walked 1 km?
Fuel consumption of average car= 8 km L^(-1)
Heat of combustion of gasoline= 50 kJ g^(-1)
Density of gasoline= 0.7g mL^(-1)
1)2km
2)0.02 km
3) 20 km
How would i solve this?
An average person expends ~100 kj to walk 1km. How far will the average car travel by the time it expends the same amount of energy (i.e. 100 kJ) as a person who walked 1 km?
Fuel consumption of average car= 8 km L^(-1)
Heat of combustion of gasoline= 50 kJ g^(-1)
Density of gasoline= 0.7g mL^(-1)
1)2km
2)0.02 km
3) 20 km
How would i solve this?
Answers
Answered by
DrBob222
Energy output of the car is 50 kJ/gram.
So you will need 2 grams to equal 100 kJ (that is, 50 kJ/g x ?g = 100 and solve for ?g).
2 grams is what volume.
mass = volume x density
2 g = v x 0.7g/mL
Solve for v. I think something like 2.85 mL but you need to confirm that to get an exact answer. Then you know the fuel consumption is 8 km/L, how far can you go with 2.85 mL?
So you will need 2 grams to equal 100 kJ (that is, 50 kJ/g x ?g = 100 and solve for ?g).
2 grams is what volume.
mass = volume x density
2 g = v x 0.7g/mL
Solve for v. I think something like 2.85 mL but you need to confirm that to get an exact answer. Then you know the fuel consumption is 8 km/L, how far can you go with 2.85 mL?
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