(a) Your formuls should have been written
W = (1/2) C (ΔV)^2
All you have to do is use it. With ΔV = 7000 V and C = 64*10^-3 F, the answer will be in Joules.
(b) Power = Work/time
(c) (Generator power)* Time = Work
(Get the Work from part (a)
Solve for the time
Lasers are used to try to produce controlled fusion reactions. These lasers require brief pulses of energy that are stored in large rooms filled with capacitors. One such room has a capacitance of 64 10-3 F charged to a potential difference of 7 kV.
(a) Given that W = 1/2CΔV2.
J, find the energy stored in the capacitors.
(b) The capacitors are discharged in 10 ns (1.0 10-8 s). What power is produced?
(c) If the capacitors are charged by a generator with a power capacity of 1.5 kW, how many seconds will be required to charge the capacitors?
2 answers
Verygood