Larry is building a frame around a rectangular picture. He will need 44 inches of wood to do the entire frame. If the frame is 12 inches long, how wide is the frame?

Answer 1

Let's assume that the width of the frame is x inches.

The perimeter of the rectangular picture with the frame is the sum of the lengths of all four sides.

Perimeter = 2(length + width)

The length of the rectangular picture is given as 12 inches.

So, the perimeter of the picture with the frame is:

44 inches = 2(12 + x + 12 + x)

44 inches = 2(24 + 2x)

44 inches = 48 + 4x

Subtracting 48 from both sides:

44 - 48 inches = 4x

-4 inches = 4x

Dividing both sides by 4:

x = -1

Since the width of the frame cannot be negative, this means that there is no solution to this problem.

Therefore, the question is not possible to solve.