Larry invested a total of $5000 in three stocks during the first year the first stock increasing value by 8% the second stock increase by 6% and the third stock increase by 1% in the first year he earn a profit $310 if Larry invested the same amount in the stock that increased by 6% as he invested in the stock that increased by 1% how much did he invest in the stock?

Answer 1

Let the amounts at 1,6,8% be x,y,z. We have:

x+y+z = 5000
.01x + .06y + .08z = 310
x = y

Now just solve for x,y,z