First, we need to calculate the total number of treats Lana has in the drawer: 4 pig’s ears + 2 rawhide twists + 6 busy bones + 4 dental chews = 16 treats.
The number of treats that are not pig’s ears is 16 - 4 = 12.
Therefore, the probability that Lana will NOT choose a pig’s ear is 12/16 or 3/4, which simplifies to 75%.
Lana has several dog treats in a drawer: 4 pig’s ears, 2 rawhide twists, 6 busy bones, and 4 dental chews. She will randomly choose 1 treat from the drawer for her dog, Koda.%0D%0A%0D%0AWhat is the probability that Lana will NOT choose a pig’s ear?
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1 answer