L = k/m + b
3 = k/2 + b
9 = k/5 + b
------------- subtract
-6 = k/2 - k/5 = 5 k/10 - 2 k/10 = 3 k/10
k=-20
3 = -10 + b
b = 13
so
L = -20/m + 13
so put in 1 for L and see what you get for m
L varies partly inversely as m and is partly constant. When L=3,M=2 and when m=2 and when L=9,m=5.find M when L=1
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