l varies partly inversely as m and is partly constant when l=3,m=2 and when l=9,m=5.find m when l=1.

Answer 1

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Once is enough, thank you.
Repeated postings will not get faster or better responses.

Answer 2

L varies

Answer 3

partly inversely as M and is partly constant.

We can represent this relationship between L and M using the formula:

L = k(M/h)

where k and h are constants.

To find k and h, we can use the given information that when L=3 and M=2, and when L=9 and M=5:

3 = k(2/h)

9 = k(5/h)

We can solve for h in the first equation:

3h = 2k

h = (2/3)k

Substitute this into the second equation:

9 = k(5/((2/3)k))

9 = k(7.5)

k = 1.2

Now we can find h:

3 = 1.2(2/h)

h = 4

So the formula for L in terms of M is:

L = (1.2M/4)

Answer 4

L varies partly inversely as M and is partly constant when L=3,M=2 and when L=9,M=5 Fins M when L=1

Answer 5

We can use the formula L = k(M/h) to solve for the value of M when L=1.

From the given information, we know that when L=3 and M=2, and when L=9 and M=5:

3 = k(2/h)

9 = k(5/h)

We can solve for h in the first equation:

3h = 2k

h = (2/3)k

Substitute this into the second equation:

9 = k(5/((2/3)k))

k = 1.2

Now we know that:

L = (1.2M/4)

We can plug in L = 1 and solve for M:

1 = (1.2M/4)

M = (4/1.2)

M = 3.33 (rounded to two decimal places)

Therefore, when L=1, M is approximately equal to 3.33.