1) To solve the equation 12 + 3x = 6x - 4(x - 5), we can begin by distributing the -4 to the terms inside the parentheses. This gives us 12 + 3x = 6x - 4x + 20. Next, we can combine like terms on the right side of the equation to get 12 + 3x = 2x + 20. To isolate the variable x, we can subtract 2x from both sides of the equation, resulting in 12 + x = 20. Lastly, we subtract 12 from both sides to solve for x, giving us x = 8.
2) In the equation m + 3 = m + 4, we can simplify it by subtracting m from both sides of the equation. This gives us 3 = 4. Since 3 is not equal to 4, no value of m can be substituted to make this a true number sentence.
3) Let's say the number of students attending the dance is represented by s. The equation to determine the number of students can be written as 3000 + 15s = 12000. This equation represents the cost of renting the hall ($3000) added to the cost per student for food and drinks ($15s) equals the total amount raised ($12000) by the freshman class. To solve for s, we can start by subtracting 3000 from both sides of the equation, resulting in 15s = 9000. Finally, we divide both sides by 15 to find that s = 600. Therefore, 600 students can attend the school dance.
l need help with 3 Questions
1) Solve the equation for x. Make sure to show work.
12+3x=6x−4(x−5)
2)For the equation m+3=m+4, can you substitute a value for m to make this a true number sentence? Make sure to explain your answer.
3)The freshman class raised funds for a school dance. It costs $3,000 to rent out the hall plus $15 per student for food and drinks. The freshman class raised $12,000. Write and solve an equation to determine how many students can attend the school dance.
1 answer
1 answer