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Kyle traveled at an average of 45 miles per hour for 1.5 hours and then traveled at an average speed of 50 miles per hour for 2...Asked by joey
Kyle traveled at an average of 45 miles per hour for 1.5 hours and then traveled at an average speed of 50 miles per hour for 2.5 hours. What was the total distance in miles that Kyle traveled during this time
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Answered by
GPT-4o mini
To find the total distance that Kyle traveled, we can calculate the distance for each segment of his trip separately and then add those distances together.
First, we calculate the distance traveled at 45 miles per hour for 1.5 hours:
\[
\text{Distance}_1 = \text{Speed} \times \text{Time} = 45 \, \text{miles/hour} \times 1.5 \, \text{hours} = 67.5 \, \text{miles}
\]
Next, we calculate the distance traveled at 50 miles per hour for 2.5 hours:
\[
\text{Distance}_2 = \text{Speed} \times \text{Time} = 50 \, \text{miles/hour} \times 2.5 \, \text{hours} = 125 \, \text{miles}
\]
Now, we add the two distances together to find the total distance traveled:
\[
\text{Total Distance} = \text{Distance}_1 + \text{Distance}_2 = 67.5 \, \text{miles} + 125 \, \text{miles} = 192.5 \, \text{miles}
\]
Thus, the total distance that Kyle traveled is \(\boxed{192.5}\) miles.
First, we calculate the distance traveled at 45 miles per hour for 1.5 hours:
\[
\text{Distance}_1 = \text{Speed} \times \text{Time} = 45 \, \text{miles/hour} \times 1.5 \, \text{hours} = 67.5 \, \text{miles}
\]
Next, we calculate the distance traveled at 50 miles per hour for 2.5 hours:
\[
\text{Distance}_2 = \text{Speed} \times \text{Time} = 50 \, \text{miles/hour} \times 2.5 \, \text{hours} = 125 \, \text{miles}
\]
Now, we add the two distances together to find the total distance traveled:
\[
\text{Total Distance} = \text{Distance}_1 + \text{Distance}_2 = 67.5 \, \text{miles} + 125 \, \text{miles} = 192.5 \, \text{miles}
\]
Thus, the total distance that Kyle traveled is \(\boxed{192.5}\) miles.
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