Kp=1.78 at 250 degrees for the decomposition reaction, PCl5(g)-PCl3(g)+Cl2(g. Calculate the percentage of reactant that remains if 10.0 moles of starting material are placed in a closed vessel at this temperature and 2.00 atm pressure. Also, determine the value of Kc for this reaction at 250 degrees.

Question

Kp=1.78 at 250 degrees for the decomposition reaction, PCl5(g)->PCl3(g)+Cl2(g. Calculate the percentage of reactant that remains if 10.0 moles of starting material are placed in a closed vessel at this temperature and 2.00 atm pressure. Also, determine the value of Kc for this reaction at 250 degrees.

DrBob222 · Answer

Set up an ICE chart and substitute into the Kp expression, then solve for x. For converting Kp to Kc, look in your text or notes for the formula to do that.