K unchanged
Mn goes from +7 to +2 gained five electrons
Cl goes from -1 to zero (but it is a Cl2).
I agree with 10
KMnO4 + HCl → MnCl2 + Cl2 + H2O + KCl
If the reaction occurs in an acidic solution where water and H+ ions are added to the half-reactions to balance the overall reaction, how many electrons are transferred in the balanced reduction half-reaction?
The answer I got is 5*2 which equals 10
2 answers
This one looks ok to me and I get 10 easily, also. I'm still confused by the previous problem.