kind of need some guidance with "PART C" below:
A) The bond angles in CH4 are 109.5degrees, while the bond angles in NH3 are 107 degrees.
Based on this information, which type of repulsion must be greater:
BP-BP
LP-BP
((((for this part I got: "LP-BP" as the correct answer))))
&
B) The bond angles in NH3 are 107degrees, while the bond angles in H2O are 105degrees. Based on this information, which type of repulsion must be greater?
LP-BP
LP-LP
((((for this part I got "LP-LP" as the correct answer))))
What I need help with, however, is:
C) Based on your answers to Parts A and B, arrange the three types of repulsion in order of increasing magnitude:
i) LP-BP < BP-BP < LP-LP
ii)BP-BP < LP-LP < LP-BP
iii) LP-LP < LP-BP < BP-BP
iv) BP-BP < LP-BP < LP-LP
----I think that the correct order should be: BP-BP < LP-BP < LP-LP
Is this correct??? Bonded-Bonded pairs sould not have a lot of repulsion if there are no lone pairs, correct??? Then as I asnwered in Part A - LP-BP & then as I asnwered in Part B - LP-LP???
& how can I tell/know for certain??? Any help is HUGELY appreciated!!
(BP = bonded pair LP = lone pair)
2 answers