Kimberly ran 4/5 of the way around the track before getting tired and slowing her pace. What percentage of the track did she run at a slower pace?(1 point)
1 answer
Kimberly ran 4/5 of the track, which is equivalent to 80% (4/5 = 80/100 = 80%). Therefore, she ran 80% of the track at a faster pace and the remaining 20% at a slower pace.