q = mass Cu x specific heat Cu x (Tfinal - Tinitial)
q = 165 x specific heat Cu (you look it up) x (Tf - Ti) = ?
Post your work if you get stuck.
Note: I have no idea what (T-final - Tinitial) means, either exactly or otherwise. I've answered several heat question today and I thought perhaps I made a typo; however, I looked, I thought, at all of my responses and I didn't see a typo. If you are the one that made a typo and you meant to ask about the meaning of (Tfinal - Tintial), here it is.
Tinitial is the initial temperataure (starting temperature in the problem) while Tfinal is the final temperature (ending temperature in the problem). In this Cu problem, Tinitial or Ti is 28 C and Tfinal or Tf is 185 C. Hope that clears things up.
kilojoules to heat 165 g of copper from 28 ∘C to 185 ∘C.
Side note question what is (T-final-Tinitial) means exactly?
3 answers
So here's my problem to that question..
(165g) (4.184) (185-28) = 108386.52
and then divide that by 1000 so it would be like this.. 108386.52/1000 and that equals to 108.38652 and then its asking for 3 SFs wouldn't that be 108 KJ?
(165g) (4.184) (185-28) = 108386.52
and then divide that by 1000 so it would be like this.. 108386.52/1000 and that equals to 108.38652 and then its asking for 3 SFs wouldn't that be 108 KJ?
Yes. Exactly. Well done.