2.789 g KHP x (1 mol KHP/204.22 g KHP) = 0.0137 mol KHP
27.77 mL NaOH x (M NaOH) = 0.0137 mol KHP
M NaOH = 0.0137 mol KHP/27.77 mL NaOH = 0.049 M NaOH
2.543 g KHP x (1 mol KHP/204.22 g KHP) = 0.0124 mol KHP
23.22 mL NaOH x (M NaOH) = 0.0124 mol KHP
M NaOH = 0.0124 mol KHP/23.22 mL NaOH = 0.053 M NaOH
2.612 g KHP x (1 mol KHP/204.22 g KHP) = 0.0128 mol KHP
27.12 mL NaOH x (M NaOH) = 0.0128 mol KHP
M NaOH = 0.0128 mol KHP/27.12 mL NaOH = 0.047 M NaOH
The average concentration of NaOH solution is 0.049 M NaOH.
KHP is a monoprotic acid with a molar mass of 204.22 g/mol. The titration data are as following.
The average concentration of NaOH solution is
M.
1 2 3
mass of KHP (g) 2.789 2.543 2.612
vol NaOH used (mL) 27.77 23.22 27.12
You didn't ask a question but I assume you are to calculate the molarity of NaOH.
mols KHP = mols NaOH
mols KHP = g/molar mass
mols NaOH = volume NaOH x M NaOH.
Post your work if you get stuck.
1 answer