To arrive at a shared binomial in Step 3, Kevin should consider how he factored the terms in Step 2. In Step 3, he ended up with \(3x(2x-1) + 2(-2x+1) = 0\), which shows that he factored the terms in such a way that they do not share a common binomial factor.
The appropriate change Kevin should make is to change the grouping of pairs in Step 2. This would allow him to group the terms in a way that may yield a common binomial factor when he factors them in Step 3.
Therefore, the correct response is:
Change the grouping of pairs in Step 2.