Let X be the amount of money Kenneth had at first.
Kenneth spent X/7 on food + $180 + X/5 on a new table + $1000 on a new television screen.
Kenneth saved X - (X/7 + $180 + X/5 + $1000) = $1400 in the bank.
Multiplying through the parentheses, we get X - X/7 - $180 - X/5 - $1000 = $1400
Combining like terms, we get X - X/7 - X/5 = $3580
Combining the X terms, we get 35X/35 - 5X/35 - 7X/35 = $3580
Combining like terms, we get 23X/35 = $3580
Multiplying both sides by 35, we get 23X = $125300
Dividing both sides by 23, we get X = $<<5450=5450>>5450. Answer: \boxed{5450}.
Kenneth had some money. He spent 1/7 of his money on food and $180 on
transport. He spent 1/5 of the remaining money on a new table. He also spent $1000 on a new television screen. He saved the remaining $1400 in the bank. How much money did Kenneth have at first?
3 answers
Kenneth's total money = Food + Transport + Table + Television + Bank Savings
= (1/7 * Money) + 180 + (1/5 * (Money - 180)) + 1000 + 1400
= (1/7 * Money) + 180 + (1/5 * Money) - (1/5 * 180) + 1000 + 1400
= (1/7 * Money) + (2/5 * Money) + 1000 + 1400
= (7/7 * Money) + 1000 + 1400
= Money + 1000 + 1400
= Money + 2400
= 3710
Therefore, Kenneth had $3710 at first.
= (1/7 * Money) + 180 + (1/5 * (Money - 180)) + 1000 + 1400
= (1/7 * Money) + 180 + (1/5 * Money) - (1/5 * 180) + 1000 + 1400
= (1/7 * Money) + (2/5 * Money) + 1000 + 1400
= (7/7 * Money) + 1000 + 1400
= Money + 1000 + 1400
= Money + 2400
= 3710
Therefore, Kenneth had $3710 at first.
Apologies for the mistake in my previous response.
Your solution is correct. Kenneth had $3710 at first.
Your solution is correct. Kenneth had $3710 at first.
3 answers