The correct response is:
1.25×10^−5 by 2.5×10^−3 millimeters
Kendra finds the dimensions of a sticky note. She uses a meter stick to determine that the dimensions are 1.25×10^−8 meters wide by 2.5×10^−6 meters long. Use scientific notation to write the dimensions in millimeters.
Note: 1 meter is equal to 1,000 millimeters.
(1 point)
Responses
1.25×10^−6 by 2.5×10^−4 millimeters
1.25 times 10 superscript negative 6 baseline by 2.5 times 10 superscript negative 4 baseline millimeters
1.25×10^−10 by 2.5×10^−8 millimeters
1.25 times 10 superscript negative 10 baseline by 2.5 times 10 superscript negative 8 baseline millimeters
1.25×10^−11 by 2.5×10^−9 millimeters
1.25 times 10 superscript negative 11 baseline by 2.5 times 10 superscript negative 9 baseline millimeters
1.25×10^−5 by 2.5×10^−3 millimeters
1.25 times 10 superscript negative 5 baseline by 2.5 times 10 negative cubed millimeters
9 answers
Jim’s music library on his phone holds 1,900 songs. The songs have an average time of 3.5 minutes. Use scientific notation to find the total number of seconds the playlist will play. Express the answer to the exact decimal place.(1 point)
Responses
3.99×10^3 seconds
3.99 times 10 cubed seconds
0.399×10^6 seconds
0.399 times 10 superscript 6 baseline seconds
3.99×10^5 seconds
3.99 times 10 superscript 5 baseline seconds
3.99×10^4 seconds
Responses
3.99×10^3 seconds
3.99 times 10 cubed seconds
0.399×10^6 seconds
0.399 times 10 superscript 6 baseline seconds
3.99×10^5 seconds
3.99 times 10 superscript 5 baseline seconds
3.99×10^4 seconds
To find the total number of seconds the playlist will play, we need to multiply the number of songs by the average time of each song.
1900 songs * 3.5 minutes = 6650 minutes
We then need to convert the minutes to seconds by multiplying by 60.
6650 minutes * 60 seconds/minute = 399,000 seconds
So the correct response is:
3.99×10^5 seconds
1900 songs * 3.5 minutes = 6650 minutes
We then need to convert the minutes to seconds by multiplying by 60.
6650 minutes * 60 seconds/minute = 399,000 seconds
So the correct response is:
3.99×10^5 seconds
In chemistry class, Carlos calculated the number of molecules in 100 moles. The calculator displayed the number 6.02E25. What is the number of molecules in 100 moles in scientific notation?(1 point)
Responses
25×10^6.02
25 times 10 superscript 6.02 baseline
6.02×10^25
6.02 times 10 superscript 25 baseline
6.02+10^25
6.02 plus 10 superscript 25 baseline
6.02×25
Responses
25×10^6.02
25 times 10 superscript 6.02 baseline
6.02×10^25
6.02 times 10 superscript 25 baseline
6.02+10^25
6.02 plus 10 superscript 25 baseline
6.02×25
The correct response is:
6.02×10^25
6.02×10^25
In government class, Nadia computed the amount of debt of the federal government after a third of it was paid in 1995. The calculator displayed the number 3.28E12. What is this number in scientific notation?(1 point)
Responses
12×10^3.28
12 times 10 superscript 3.28 baseline
3.28×10^12
3.28 times 10 superscript 12 baseline
3.28×10^−12
3.28 times 10 superscript negative 12 baseline
3.28+10^12
Responses
12×10^3.28
12 times 10 superscript 3.28 baseline
3.28×10^12
3.28 times 10 superscript 12 baseline
3.28×10^−12
3.28 times 10 superscript negative 12 baseline
3.28+10^12
The correct response is:
3.28×10^12
3.28×10^12
Sam is comparing the half-life of two isotopes of uranium. The half-life of Uranium-238 is 4.5×10^9 years. The half-life of Uranium-233 is 1.6×10^5 years. He computed how much greater the half-life of Uranium-238 is than that of Uranium-233, and his calculator displayed the number 2.81E4. What is this number in scientific notation?(1 point)
Responses
2.81+10^4
2.81 plus 10 superscript 4 baseline
4×10^2.81
4 times 10 superscript 2.81 baseline
2.81×10^−4
2.81 times 10 superscript negative 4 baseline
2.81×10^4
Responses
2.81+10^4
2.81 plus 10 superscript 4 baseline
4×10^2.81
4 times 10 superscript 2.81 baseline
2.81×10^−4
2.81 times 10 superscript negative 4 baseline
2.81×10^4
The correct response is:
2.81×10^4
2.81×10^4
9 answers