Ken had $60 more than Jordan. Ken spent 7/8 of his money and Jordan spent 3/5 of his money. Ken had half as much money as Jordan. Find the amount of money that Jordan had at first.

Answer 1

Jordan had $90 at first.

Answer 2

Suppose the amount of money that Jordan had x at finst.
Ken had (x + 60) at first
(1 - 7/8) (x + 60) = 1/2 * (1 - 3/5)x
0.125x + 7.5 = 0.2x
0.075x = 7.5
x = 100

Answer 3

Jordan had --- x
Ken had ---- x+60

after the spending
Jordan has 2/5 x
Ken has 1/8 (x+60)

1/8 (x+60) = 1/2 (2/5)x = 1/5 x
times 40
5(x+60) = 8x
5x +300 = 8x
300 = 3x
x =100

I agree with the 2nd poster, and the AI is wrong