Question

Kelly is attending a fall carnival with only $10. Admission into the carnival is $3 and each game inside the carnival costs $0.25. Which inequality can be used to determine the maximum number games Kelly can play? (1 point) Responses 0.25x+3≤10 0 point 2 5 x plus 3 is less than or equal to 10 0.25x+3≥10 0 point 2 5 x plus 3 is greater than or equal to 10 0.25x+3<10 0.25x+3<10 0.25x+3>10 0 point 2 5 x plus 3 is greater than 10 Question 2 (1 point) Kelly has enough money to play at most games.

Answer 1

To determine the maximum number of games Kelly can play, we need to set up an inequality based on her total budget and the costs involved.

1. Kelly has $10 to spend.
2. The admission to the carnival costs $3.
3. Each game costs $0.25.

So, after paying for admission, the amount Kelly has left to spend on games is:

\[ 10 - 3 = 7 \]

Let \(x\) represent the number of games Kelly plays. Since each game costs $0.25, the total cost for \(x\) games would be \(0.25x\).

Thus, the inequality that models how much money she can spend on games is:

\[ 0.25x \leq 7 \]

Now, if you consider the original context of how much money she has in total, we would include the admission cost in the inequality:

\[ 0.25x + 3 \leq 10 \]

Rearranging this gives:

\[ 0.25x \leq 7 \]

This means the inequality that can be used to determine the maximum number of games Kelly can play is:

\[ 0.25x + 3 \leq 10 \]

For Question 2, to find the maximum number of games she can play, we can solve the inequality \(0.25x + 3 \leq 10\):

Subtract 3 from both sides:

\[ 0.25x \leq 7 \]

Now, divide both sides by 0.25 (or multiply by 4):

\[ x \leq 28 \]

So Kelly can play at most 28 games.