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3. Kelly and eddie are each saving money for a motorcycle the total amount of money in dollars that kelly will save over x week...Question
Kelly and eddie are each saving money for a motorcycle. the total amount of money, in dollars, that kelly will save over x weeks is modeled by the function f(x)=60+50x. The total amount of money, in dollars, that eddie will save over x weeks is modeled by the function g(x)=2^x. Graph the functions in the same coordinate plane to determine when f(x)=g(x). After how many weeks, rounded to the nearest integer, will they have saved the same amount of money?
1)510 weeks
2)1 week
3)60 weks
4)9 weeks
1)510 weeks
2)1 week
3)60 weks
4)9 weeks
Answers
Answered by
GPT-4o mini
To find out when Kelly and Eddie will have saved the same amount of money, we need to set the two functions equal to each other:
\[ f(x) = g(x) \]
Using the functions given:
\[ 60 + 50x = 2^x \]
Next, we'll solve this equation for \( x \). Because we have a linear equation on one side and an exponential equation on the other, we may need to use numerical methods or graphing to find the intersection point.
1. **Graphing the functions**:
- For \( f(x) = 60 + 50x \): This is a linear function that starts at \( 60 \) when \( x = 0 \) and increases by \( 50 \) for each additional week.
- For \( g(x) = 2^x \): This is an exponential function that starts at \( 1 \) when \( x = 0 \) and grows rapidly as \( x \) increases.
2. **Finding the intersection numerically**:
You can use graphing software, a graphing calculator, or numerical methods to solve \( 60 + 50x = 2^x \). However, we'll also try a few values by hand:
- **For \( x = 1 \)**:
\( f(1) = 60 + 50(1) = 110 \)
\( g(1) = 2^1 = 2 \)
- **For \( x = 2 \)**:
\( f(2) = 60 + 50(2) = 160 \)
\( g(2) = 2^2 = 4 \)
- **For \( x = 5 \)**:
\( f(5) = 60 + 50(5) = 310 \)
\( g(5) = 2^5 = 32 \)
- **For \( x = 8 \)**:
\( f(8) = 60 + 50(8) = 460 \)
\( g(8) = 2^8 = 256 \)
- **For \( x = 9 \)**:
\( f(9) = 60 + 50(9) = 510 \)
\( g(9) = 2^9 = 512 \)
- **For \( x = 10 \)**:
\( f(10) = 60 + 50(10) = 560 \)
\( g(10) = 2^{10} = 1024 \)
From our calculations, we see that:
- At \( x = 8 \), \( f(8) = 460 \) and \( g(8) = 256 \)
- At \( x = 9 \), \( f(9) = 510 \) and \( g(9) = 512 \)
- At \( x = 10 \), \( f(10) = 560 \) and \( g(10) = 1024 \)
The value of \( x \) where they have saved approximately the same amount of money falls between \( 8 \) and \( 9 \). Rounding to the nearest integer, they will have saved the same amount of money after:
**Answer**: 9 weeks
\[ f(x) = g(x) \]
Using the functions given:
\[ 60 + 50x = 2^x \]
Next, we'll solve this equation for \( x \). Because we have a linear equation on one side and an exponential equation on the other, we may need to use numerical methods or graphing to find the intersection point.
1. **Graphing the functions**:
- For \( f(x) = 60 + 50x \): This is a linear function that starts at \( 60 \) when \( x = 0 \) and increases by \( 50 \) for each additional week.
- For \( g(x) = 2^x \): This is an exponential function that starts at \( 1 \) when \( x = 0 \) and grows rapidly as \( x \) increases.
2. **Finding the intersection numerically**:
You can use graphing software, a graphing calculator, or numerical methods to solve \( 60 + 50x = 2^x \). However, we'll also try a few values by hand:
- **For \( x = 1 \)**:
\( f(1) = 60 + 50(1) = 110 \)
\( g(1) = 2^1 = 2 \)
- **For \( x = 2 \)**:
\( f(2) = 60 + 50(2) = 160 \)
\( g(2) = 2^2 = 4 \)
- **For \( x = 5 \)**:
\( f(5) = 60 + 50(5) = 310 \)
\( g(5) = 2^5 = 32 \)
- **For \( x = 8 \)**:
\( f(8) = 60 + 50(8) = 460 \)
\( g(8) = 2^8 = 256 \)
- **For \( x = 9 \)**:
\( f(9) = 60 + 50(9) = 510 \)
\( g(9) = 2^9 = 512 \)
- **For \( x = 10 \)**:
\( f(10) = 60 + 50(10) = 560 \)
\( g(10) = 2^{10} = 1024 \)
From our calculations, we see that:
- At \( x = 8 \), \( f(8) = 460 \) and \( g(8) = 256 \)
- At \( x = 9 \), \( f(9) = 510 \) and \( g(9) = 512 \)
- At \( x = 10 \), \( f(10) = 560 \) and \( g(10) = 1024 \)
The value of \( x \) where they have saved approximately the same amount of money falls between \( 8 \) and \( 9 \). Rounding to the nearest integer, they will have saved the same amount of money after:
**Answer**: 9 weeks
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