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Keith left his house for the grocery store to buy items for dinner. He rode his bike 2miles down one road, took a 90-degree tur...Question
Keith left his house for the grocery store to buy items for dinner. He rode his bike 2miles down one road, took a 90-degree turn, and rode another 2 miles down a different road before arriving at the store. If he had ridden directly to the grocery store, how much distance would he have saved? Round your answer to the nearest tenth.
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GPT-4o mini
To find the distance Keith would have saved by riding directly to the grocery store instead of following the two roads, we can use the Pythagorean theorem.
Keith rode 2 miles down one road and then took a 90-degree turn to ride another 2 miles down a different road. This forms a right triangle, where:
- One leg of the triangle (a) = 2 miles
- The other leg of the triangle (b) = 2 miles
Using the Pythagorean theorem:
\[
c = \sqrt{a^2 + b^2}
\]
Substituting in the values of \(a\) and \(b\):
\[
c = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}
\]
Calculating \(2\sqrt{2}\):
\[
2\sqrt{2} \approx 2 \times 1.414 \approx 2.828
\]
Now, this is the distance Keith would have traveled directly to the grocery store.
The distance he actually rode is:
\[
2 \text{ miles} + 2 \text{ miles} = 4 \text{ miles}
\]
To find out how much distance he saved by taking a direct route, we subtract the direct distance \(c\) from the actual distance he rode:
\[
\text{Distance saved} = 4 - 2.828 \approx 1.172
\]
Rounding this to the nearest tenth gives:
\[
\text{Distance saved} \approx 1.2 \text{ miles}
\]
Thus, the distance Keith would have saved is approximately **1.2 miles**.
Keith rode 2 miles down one road and then took a 90-degree turn to ride another 2 miles down a different road. This forms a right triangle, where:
- One leg of the triangle (a) = 2 miles
- The other leg of the triangle (b) = 2 miles
Using the Pythagorean theorem:
\[
c = \sqrt{a^2 + b^2}
\]
Substituting in the values of \(a\) and \(b\):
\[
c = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}
\]
Calculating \(2\sqrt{2}\):
\[
2\sqrt{2} \approx 2 \times 1.414 \approx 2.828
\]
Now, this is the distance Keith would have traveled directly to the grocery store.
The distance he actually rode is:
\[
2 \text{ miles} + 2 \text{ miles} = 4 \text{ miles}
\]
To find out how much distance he saved by taking a direct route, we subtract the direct distance \(c\) from the actual distance he rode:
\[
\text{Distance saved} = 4 - 2.828 \approx 1.172
\]
Rounding this to the nearest tenth gives:
\[
\text{Distance saved} \approx 1.2 \text{ miles}
\]
Thus, the distance Keith would have saved is approximately **1.2 miles**.
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