Keith left his house for the grocery store to buy items for dinner. He rode his bike 2miles down one road, took a 90-degree turn, and rode another 2 miles down a different road before arriving at the store. If he had ridden directly to the grocery store, how much distance would he have saved? Round your answer to the nearest tenth.

(1 point)
Responses

2.8 miles
2.8 miles

1.2 miles
1.2 miles

5.2 miles
5.2 miles

0 miles

1 answer

To solve this problem, we can use the Pythagorean theorem.

Keith rode 2 miles down one road and then made a 90-degree turn to ride another 2 miles down a different road. This forms a right triangle where the two roads correspond to the two legs (each 2 miles), and the direct route he would have taken to the grocery store is the hypotenuse of the triangle.

We can use the Pythagorean theorem, which states:

\[ a^2 + b^2 = c^2 \]

where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the other two sides.

In Keith's case, both \( a \) and \( b \) are 2 miles.

Calculating the hypotenuse \( c \):

\[ c^2 = 2^2 + 2^2 \] \[ c^2 = 4 + 4 \] \[ c^2 = 8 \] \[ c = \sqrt{8} \approx 2.828 \]

Thus, the direct distance he could have traveled to the grocery store is approximately 2.8 miles.

Now, to find out how much distance he saved:

The total distance he rode turning is 2 miles + 2 miles = 4 miles.

So, the distance saved by riding directly to the store instead is:

\[ \text{Distance saved} = \text{Distance ridden} - \text{Direct distance} = 4 - 2.828 \approx 1.2 \text{ miles} \]

So the answer is 1.2 miles.