The total number of customers is 3 + 21 + 46 = 70.
The probability that the next customer will pay with a debit card is 21/70, which simplifies to 3/10.
Converting 3/10 to a decimal, we get 0.30.
Therefore, the probability that the next customer will pay with a debit card as a decimal to the nearest hundredth is 0.30.
Kaylee owns a small business selling clothing. She knows that in the last week 3 customers paid cash, 21 customers used a debit card, and 46 customers used a credit card.
Based on these results, express the probability that the next customer will pay with a debit card as a decimal to the nearest hundredth.
11 answers
Round 9/32 to the nearest hundredth
To convert 9/32 to a decimal, you divide the numerator (9) by the denominator (32).
9 รท 32 = 0.28125
Rounded to the nearest hundredth, 9/32 is approximately 0.28.
9 รท 32 = 0.28125
Rounded to the nearest hundredth, 9/32 is approximately 0.28.
Based on these results, express the probability that a seventh grader chosen at random will play an instrument others than bass as a decimal to the nearest hundredth
Seventh Grade Students:
Guitar: 14
Bass: 9
Drums: 7
Keyboard: 2
Eighth Grade Students:
Guitar: 11
Bass: 9
Drums: 15
Keyboard: 10
Seventh Grade Students:
Guitar: 14
Bass: 9
Drums: 7
Keyboard: 2
Eighth Grade Students:
Guitar: 11
Bass: 9
Drums: 15
Keyboard: 10
First, we need to calculate the total number of seventh graders who play an instrument other than bass:
Total seventh graders playing an instrument = Guitar + Drums + Keyboard = 14 + 7 + 2 = 23
The probability that a seventh grader chosen will play an instrument other than bass is the number of seventh graders playing an instrument other than bass divided by the total number of seventh graders:
P(seventh grader plays an instrument other than bass) = 23 / (Guitar + Bass + Drums + Keyboard)
P(seventh grader plays an instrument other than bass) = 23 / (14 + 9 + 7 + 2) = 23 / 32
Dividing 23 by 32 gives 0.71875.
Rounded to the nearest hundredth, the probability that a seventh grader chosen at random will play an instrument other than bass is approximately 0.72.
Total seventh graders playing an instrument = Guitar + Drums + Keyboard = 14 + 7 + 2 = 23
The probability that a seventh grader chosen will play an instrument other than bass is the number of seventh graders playing an instrument other than bass divided by the total number of seventh graders:
P(seventh grader plays an instrument other than bass) = 23 / (Guitar + Bass + Drums + Keyboard)
P(seventh grader plays an instrument other than bass) = 23 / (14 + 9 + 7 + 2) = 23 / 32
Dividing 23 by 32 gives 0.71875.
Rounded to the nearest hundredth, the probability that a seventh grader chosen at random will play an instrument other than bass is approximately 0.72.
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 2 or a multiple of 5?
To find the probability that the result is a multiple of 2 or a multiple of 5, we first need to determine how many numbers fall into each category.
Multiples of 2 within 1 to 15: 2, 4, 6, 8, 10, 12, 14 (7 numbers)
Multiples of 5 within 1 to 15: 5, 10, 15 (3 numbers)
However, 10 is a common multiple of 2 and 5, so we must only count it once to avoid double counting.
So, there are 7 multiples of 2, 3 multiples of 5, and 1 common multiple of 2 and 5.
Therefore, there are 7 + 3 - 1 = 9 numbers that are either multiples of 2 or multiples of 5.
The total possible outcomes are 15 (since there are 15 equal areas on the spinner).
The probability that the result is a multiple of 2 or a multiple of 5 is 9/15, which simplifies to 3/5 or 0.6 when expressed as a decimal.
So, the probability is 0.6.
Multiples of 2 within 1 to 15: 2, 4, 6, 8, 10, 12, 14 (7 numbers)
Multiples of 5 within 1 to 15: 5, 10, 15 (3 numbers)
However, 10 is a common multiple of 2 and 5, so we must only count it once to avoid double counting.
So, there are 7 multiples of 2, 3 multiples of 5, and 1 common multiple of 2 and 5.
Therefore, there are 7 + 3 - 1 = 9 numbers that are either multiples of 2 or multiples of 5.
The total possible outcomes are 15 (since there are 15 equal areas on the spinner).
The probability that the result is a multiple of 2 or a multiple of 5 is 9/15, which simplifies to 3/5 or 0.6 when expressed as a decimal.
So, the probability is 0.6.
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the result is a multiple of 6 and a multiple of 4?
To find the multiples of both 6 and 4, we need to determine the common multiples of 6 and 4:
Multiples of 6 within 1 to 14: 6, 12
Multiples of 4 within 1 to 14: 4, 8, 12
From the above, the common multiple is 12.
There is only one number that is both a multiple of 6 and a multiple of 4, which is 12.
So, the probability that the result is a multiple of 6 and a multiple of 4 is 1 out of 14 possible outcomes.
Therefore, the probability is 1/14, which is approximately 0.0714 when expressed as a decimal.
Multiples of 6 within 1 to 14: 6, 12
Multiples of 4 within 1 to 14: 4, 8, 12
From the above, the common multiple is 12.
There is only one number that is both a multiple of 6 and a multiple of 4, which is 12.
So, the probability that the result is a multiple of 6 and a multiple of 4 is 1 out of 14 possible outcomes.
Therefore, the probability is 1/14, which is approximately 0.0714 when expressed as a decimal.
This is wrong
I apologize for the error in my previous response. Let's correct it.
The common multiples of 6 and 4 within 1 to 14 are numbers that are multiples of the least common multiple of 6 and 4 which is 12.
Multiples of 12 within 1 to 14: 12
There is only one number that is both a multiple of 6 and a multiple of 4, which is 12.
So, the probability that the result is a multiple of 6 and a multiple of 4 is 1 out of 14 possible outcomes.
Therefore, the probability is 1/14.
The common multiples of 6 and 4 within 1 to 14 are numbers that are multiples of the least common multiple of 6 and 4 which is 12.
Multiples of 12 within 1 to 14: 12
There is only one number that is both a multiple of 6 and a multiple of 4, which is 12.
So, the probability that the result is a multiple of 6 and a multiple of 4 is 1 out of 14 possible outcomes.
Therefore, the probability is 1/14.
1 answer