To analyze Kayden's shot put scenario using the provided quadratic function \( h(t) = -16t^2 + 48t + 6 \):
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Starting Point:
- The initial height of the shot put when \( t = 0 \): \[ h(0) = -16(0)^2 + 48(0) + 6 = 6 \] Thus, the start point is \((0, 6)\).
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Vertex Calculation:
- The vertex of a quadratic function in the form \( ax^2 + bx + c \) is given by \( t = -\frac{b}{2a} \).
- Here, \( a = -16 \) and \( b = 48 \): \[ t = -\frac{48}{2 \times -16} = \frac{48}{32} = 1.5 \]
- Now, substitute \( t = 1.5 \) back into the height function to find the maximum height: \[ h(1.5) = -16(1.5)^2 + 48(1.5) + 6 \] \[ h(1.5) = -16(2.25) + 72 + 6 = -36 + 72 + 6 = 42 \] Thus, the vertex is \((1.5, 42)\).
Summary of Results:
- The starting point is \((0, 6)\), which means the shot put leaves Kayden's hand at a height of 6 feet when time \( t = 0 \).
- The vertex point is \((1.5, 42)\), which indicates that the shot put will reach a maximum height of 42 feet at \( t = 1.5 \) seconds after being thrown.
Correct Option:
Looking at the options:
A: (0, 6); (1.5, 42); The shot put leaves Kayden's hand at a distance of 0 feet and a height of 6 feet and will reach a maximum height of 42 feet 1.5 seconds after being thrown.
This option accurately describes both the starting point and the vertex, along with their meanings.
Correct answer: A