Kim runs for 30 minutes, which is 30/60 = <<30/60=0.5>>0.5 hours.
So Kim runs at a distance of 12 x 0.5 = <<12*0.5=6>>6 km.
Kanye also runs at a distance of 6 km, but at 15 km per hour.
So it takes Kanye 6/15 = <<6/15=0.4>>0.4 hours to run 6 km.
Therefore, Kanye reaches Boston at 10:00 + 0.4 = <<10+0.4=10.4>>10.4 am. Answer: \boxed{10.4}.
Kanye and Kim run from Newton to Boston at 15 km per hour and 12 km per hour, respectively. Both start in Newton at 10:00 am. If Kim reaches Boston at 10:30 am, at what time does Kanye reach Boston?
5 answers
In A REAL TIme, please
Apologies for the confusion. Let's calculate the time in real-time.
Kim runs for 30 minutes, so she reaches Boston at 10:30 am.
Let's find out how much time it takes for Kanye to run the same distance of 6 km at a speed of 15 km/h.
Time = Distance / Speed
Time = 6 km / 15 km/h
Time = 0.4 hours = 0.4 x 60 minutes (since there are 60 minutes in an hour)
Time = 24 minutes
Therefore, Kanye reaches Boston at 10:00 am + 24 minutes = 10:24 am.
Kim runs for 30 minutes, so she reaches Boston at 10:30 am.
Let's find out how much time it takes for Kanye to run the same distance of 6 km at a speed of 15 km/h.
Time = Distance / Speed
Time = 6 km / 15 km/h
Time = 0.4 hours = 0.4 x 60 minutes (since there are 60 minutes in an hour)
Time = 24 minutes
Therefore, Kanye reaches Boston at 10:00 am + 24 minutes = 10:24 am.
One car went 10 miles further when traveling at 50 mph than a second car that traveled 2 hours longer at a speed of 40 mph. How long did the first car travel?
Let's call the distance traveled by the second car as D miles.
The first car went 10 miles further than the second car, so it traveled D + 10 miles.
The second car traveled for 2 hours longer than the first car, so the time it traveled is T + 2 hours.
To find the distance traveled by each car, we use the formula:
Distance = Speed x Time
For the first car:
D + 10 = 50T
For the second car:
D = 40(T + 2)
Solving the equations:
D + 10 = 50T
D = 40(T + 2)
Substituting the value of D from the second equation into the first equation:
40(T + 2) + 10 = 50T
40T + 80 + 10 = 50T
90 = 50T - 40T
90 = 10T
T = 9
Therefore, the first car traveled for 9 hours.
The first car went 10 miles further than the second car, so it traveled D + 10 miles.
The second car traveled for 2 hours longer than the first car, so the time it traveled is T + 2 hours.
To find the distance traveled by each car, we use the formula:
Distance = Speed x Time
For the first car:
D + 10 = 50T
For the second car:
D = 40(T + 2)
Solving the equations:
D + 10 = 50T
D = 40(T + 2)
Substituting the value of D from the second equation into the first equation:
40(T + 2) + 10 = 50T
40T + 80 + 10 = 50T
90 = 50T - 40T
90 = 10T
T = 9
Therefore, the first car traveled for 9 hours.