Kamore place 7mol of ammonia in 14L flask, at equilibrium 0.2 molarity of ammonium formed.write the balance chemical equation and calculate its equilibrium constant?

Answer 1

The balanced chemical equation for the reaction of ammonia (NH3) forming ammonium (NH4^+) ion is:

NH3 (g) + H2O (l) ⇌ NH4^+ (aq) + OH^- (aq)

Given that 7 mol of ammonia is placed in a 14L flask, we can calculate the initial molarity of ammonia:
Initial molarity of NH3 = 7 mol / 14 L = 0.5 M

At equilibrium, 0.2 M of ammonium ion is formed. Using the stoichiometry of the reaction, we can see that the concentration of ammonium ion at equilibrium is equal to the concentration of ammonia:

[NH4^+] = 0.2 M

From the equation, we know that the concentration of hydroxide ion (OH^-) at equilibrium is also equal to the concentration of ammonia:

[OH^-] = 0.5 M

To calculate the equilibrium constant (K) for the reaction, we can use the formula:

K = [NH4^+] * [OH^-] / [NH3]

Plugging in the values, we get:

K = (0.2) * (0.5) / (0.5) = 0.2

Therefore, the equilibrium constant for the reaction is 0.2.