Kairay created a sculpture by forming a hemisphere with a radius of 20 inches and then removing a hemisphere with a radius of 15 inches from it. Calculate the volume of his sculpture. Use 3.14 as an approximation for pi. Round your answer to the nearest whole number.(1 point)

7,065 in.3 7,065 inches cubed 16,747 in.3 16,747 inches cubed 19,363 in.3 19,363 inches cubed 9,682 in.3

1 answer

To calculate the volume of the sculpture formed by subtracting a smaller hemisphere from a larger hemisphere, we can use the formula for the volume of a hemisphere:

\[ V = \frac{2}{3} \pi r^3 \]

Step 1: Calculate the volume of the larger hemisphere (radius: 20 inches)

Using \( r = 20 \):

\[ V_{\text{large}} = \frac{2}{3} \pi (20)^3 \] \[ = \frac{2}{3} \pi (8000) \] \[ = \frac{16000}{3} \pi \]

Plugging in \( \pi \approx 3.14 \):

\[ V_{\text{large}} = \frac{16000}{3} \times 3.14 \]

Calculating \( \frac{16000 \times 3.14}{3} \):

\[ = \frac{50240}{3} \approx 16746.67 \text{ (approximately)} \]

Step 2: Calculate the volume of the smaller hemisphere (radius: 15 inches)

Using \( r = 15 \):

\[ V_{\text{small}} = \frac{2}{3} \pi (15)^3 \] \[ = \frac{2}{3} \pi (3375) \] \[ = \frac{6750}{3} \pi \]

Again, plugging in \( \pi \approx 3.14 \):

\[ V_{\text{small}} = \frac{6750}{3} \times 3.14 \]

Calculating \( \frac{6750 \times 3.14}{3} \):

\[ = \frac{21195}{3} \approx 7065 \text{ (approximately)} \]

Step 3: Calculate the volume of the sculpture

The volume of the sculpture is:

\[ V_{\text{sculpture}} = V_{\text{large}} - V_{\text{small}} \]

Using the approximations calculated:

\[ V_{\text{sculpture}} \approx 16746.67 - 7065 \approx 9681.67 \]

Final Calculation

Rounding to the nearest whole number:

\[ V_{\text{sculpture}} \approx 9682 \text{ cubic inches} \]

Thus, the volume of Kairay's sculpture is approximately 9,682 inches cubed.