Let KL = 5cos(-60°) + 5sin(-60°) i
and LM = 5cos30° + 5sin30° i
KL+LM = 6.83-1.83i
so the bearing is 90-θ, where
tanθ = -1.83/6.83
That makes the bearing 90-(-15) = 105°
k,l and m are point in the same horizontal plane the bearing of l from k is 150 degree and bearing of m from l is 60 degree if kl equal to 5 meter and lm equal to 3 meter find the bearing of m from k,correct to the nearest degree.
1 answer