K= 6.9x10^10 which way does this dominate to right or left? for equilibrium constant? this is a hw problem i just don't understand
2 answers
can anybody help me with this?
Remember that Keq = (products)/(reactants). For K to be a very large number (6.9 x 10^10 is a huge number), products must be large and reactants must be small so the reaction dominates on the product side, or if we write the equation as
reactants ==> products, we would say the reaction was far to the right. (Note: The only way you can get a large number out of a fraction is for the numerator to be large and/or the denominator to be small. The only way to get a small number out of a fraction is to have the numerator small and/or the denominator large.)
For a very small number, for example, 1.6 x 10^-10, a VERY small number), then products would be small and reactants would be large and we would say the reaction was far to the left (meaning it hardly reacted at all. If this isn't clear, repost a separate question and give specifics about what you don't understand.
reactants ==> products, we would say the reaction was far to the right. (Note: The only way you can get a large number out of a fraction is for the numerator to be large and/or the denominator to be small. The only way to get a small number out of a fraction is to have the numerator small and/or the denominator large.)
For a very small number, for example, 1.6 x 10^-10, a VERY small number), then products would be small and reactants would be large and we would say the reaction was far to the left (meaning it hardly reacted at all. If this isn't clear, repost a separate question and give specifics about what you don't understand.
1 answer