Asked by Kieran
Just making sure im doing things right. suppose that
f(x)=2x^2+1/ãx+1/4 x^3-x+1 Caclulate
f '(1)
So far i have 4x+(ãx^-1)+3/4 x^2-1+0
then i substituted my 1 in and came out with 4 3/4
f(x)=2x^2+1/ãx+1/4 x^3-x+1 Caclulate
f '(1)
So far i have 4x+(ãx^-1)+3/4 x^2-1+0
then i substituted my 1 in and came out with 4 3/4
Answers
Answered by
Steve
what is ã ?
also, add some parentheses. It's not clear what f(x) is
also, add some parentheses. It's not clear what f(x) is
Answered by
Kieran
sorry about that a shouldnt b in there it should be
f(x)=(2x^2)+(1/sqrt(x))+[(1/4)x^3]-x+1
the a thing was supposed to be a sqrt but i guess it doesnt copy over from work
f(x)=(2x^2)+(1/sqrt(x))+[(1/4)x^3]-x+1
the a thing was supposed to be a sqrt but i guess it doesnt copy over from work
Answered by
Reiny
Ok
f(x) = 2x^2 + 1/√x + (1/4)x^3 - x + 1
= 2x^2 + x^(-1/2) + (1/4)x^3 - x + 1
f'(x) = 4x - (1/2)x^(-3/2) + (3/4)x^2 - 1
f'(1) = 4 - (1/2)(1) + 3/4 - 1
= 13/4
f(x) = 2x^2 + 1/√x + (1/4)x^3 - x + 1
= 2x^2 + x^(-1/2) + (1/4)x^3 - x + 1
f'(x) = 4x - (1/2)x^(-3/2) + (3/4)x^2 - 1
f'(1) = 4 - (1/2)(1) + 3/4 - 1
= 13/4
Answered by
Kieran
I could be wrong but im not sure i came up with 1/4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.