Just like the efficiency can be used to tell how 'good' an engine is, the Coefficient of Performance can be used to compare refrigerators. If a refrigerator requires 1.21×104 J of work to remove 3.23×104 J of energy from the inside of a refrigerator, what is the coefficient of performance of the refrigerator?

Question

2.How much energy is transferred into the hot reservoir (ie., the kitchen)? Cant figure out how to do this part

Answer 1

3.23x104J / 1.21x104 = 2.66