log_5(x^2) + 4log_5(x) = 12
2log_5(x) + 4log_5(x) = 12
6log_5(x) = 12
log_5(x) = 2
x = 5^2 = 25
Just learned log rules and I don't get it. How do you solve log5x^2 + 4log5x = 12 ? Thanks in advance.
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