#1 see your previous post
#2: sin(cos^-1(1-x))
Let cosA = 1-x
Draw a triangle with angle A such that the adjacent leg is (1-x) and the hypotenuse is 1. Then the opposite leg is √(1 - (1-x)^2) = √(2x-x^2)
Now you can tell sinA.
#3. Use the law of sines. If the desired angle is A, then
sinA/10 = sin67°/15
Just a few questions im having trouble with
1. sqrt(6-3x)-2=0
A. 2/3
B. 2
C. 10/3
D. 4
2. Using a reference triangle, find the exact value of the expression: sin(cos^-1(1-x))
A. sqrt(x(2+x)
B.1/sqrt(x(2+x))
C.1/sqrt(2+x)
D.sqrt(x(2-x))
3. The ladder of a slide forms a 67 degree angle with the ground. The distance from the top of the ladder to the bottom of the ladder is 10 feet. The slide is 15 feet long. What angle does the slide make with the ground?
A. 71.9
B.47.9
C.37.9
D.23.0
1 answer
3 answers