Vi = 24 sin 32 = 12.72 m/s
v = Vi + a t
so at top
0 = 12.72 - 9.81 t
t = 1.3 seconds rising
h = 1.5 + 12.72(1.3) - .5(9.81)(1.3^2)
h = 1.5 + 16.5 - 8.3
h = 9.7 m
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 24 m/s at an angle 32 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.
What is the maximum height the ball goes above the ground?
1 answer
1 answer