Oh good grief, feet :( old text
had initial speed 16 ft/s up ? I guess ?
h = 32 + 16 t - 16 t^2
0 = 32 + 16 t - 16 t^2
solve quadratic
t = [ -16 +/- sqrt ( 256+2048) ] /-32
t = 2 seconds
v = dh/dt = 16 - 32 t
= 16 - 64
= -48 ft/s
Joshua jumps from a platform diving board that is 32 feet above the water. The position of the diver can be modeled by s(t) = -16t2+16t+32, where s is his position and t is the seconds that have gone by since he jumped.
When does the diver hit the water, and what was his velocity?
1 answer