Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24inches what is the surface area of the rain barrel use 3.14 for and round to the nearest tenth

Answer 1

To find the surface area of the rain barrel, we need to calculate the area of the two circular ends and the lateral surface area.

1. Area of the circular ends:
The radius of the circular ends is half of the diameter, so the radius is 24/2 = 12 inches.

Area of one circular end = πr^2
Area of one circular end = 3.14 x 12^2
Area of one circular end = 3.14 x 144
Area of one circular end = 452.16 square inches

Since there are two circular ends, the total area of the circular ends is:
Total area of circular ends = 2 x 452.16
Total area of circular ends = 904.32 square inches

2. Lateral surface area:
The lateral surface area of a cylinder is given by the formula: 2πr x h, where r is the radius and h is the height.

Lateral surface area = 2 x 3.14 x 12 x 48
Lateral surface area = 3611.52 square inches

Total surface area of the rain barrel:
Total surface area = Total area of circular ends + Lateral surface area
Total surface area = 904.32 + 3611.52
Total surface area = 4515.84 square inches

Therefore, the surface area of the rain barrel is approximately 4515.8 square inches when rounded to the nearest tenth.