Jordan has a total of one hundred thirty-eight nickels, dimes, and quarters. He has a total of $13.80. He has two times as many dimes as quarters and one-third as many quarters as nickels. How many of each coin does he have?
3 answers
Jordan has 90 nickels, 40 dimes, and 8 quarters.
AAAaannndd the bot gets it wrong yet again!
the coins don't add up to $13.80, and 40 is not two times 8
n+d+q = 138
5n+10d+25q = 1380
d = 2q
n = 3q
69 nickels, 46 dimes, 23 quarters
the coins don't add up to $13.80, and 40 is not two times 8
n+d+q = 138
5n+10d+25q = 1380
d = 2q
n = 3q
69 nickels, 46 dimes, 23 quarters
Wrong!
That does not total for a value $13.80
The human way of doing it correctly:
number of quarters --- x
number of dimes ---- 2x
number of nickels ---- 138 - 3x
25x + 20x + 5(138-3x) = 1380
30x = 690
x = 23
so 23 quarters, 46 dimes and 69 nickels
check: total = 23+46+69 = 138 , check!
value: 23(25) + 46(10) + 69(5) = 1380 , check!
My answer is correct
btw, the information that there are 1/3 as many quarters as nickels is
correct but redundant data.
That does not total for a value $13.80
The human way of doing it correctly:
number of quarters --- x
number of dimes ---- 2x
number of nickels ---- 138 - 3x
25x + 20x + 5(138-3x) = 1380
30x = 690
x = 23
so 23 quarters, 46 dimes and 69 nickels
check: total = 23+46+69 = 138 , check!
value: 23(25) + 46(10) + 69(5) = 1380 , check!
My answer is correct
btw, the information that there are 1/3 as many quarters as nickels is
correct but redundant data.
1 answer