Let's assume the constant rate at which Joker warms up is represented by the variable "x" (in miles per minute).
Therefore, the equation for the distance Joker jogs during his warm-up is:
Distance = Rate × Time
Distance = x × 16
Next, let's assume the constant rate at which Joker runs is represented by the variable "y" (in miles per minute).
Therefore, the equation for the distance Joker runs during his workout is:
Distance = Rate × Time
Distance = y × 20
Since the total distance Joker warms up and runs is 2 miles for jog + 5 miles for the run = 7 miles, we can create another equation:
Distance = 7
Combining all the equations, we have:
x × 16 + y × 20 = 7
Therefore, the function equation that represents this scenario is:
16x + 20y = 7
Joker has a workout when he trains for track. He warms up with a light jog for 2 miles at a constant rate for 16 minutes. Then he stretches for 5 minutes before running 5 miles at a constant rate for 20 minutes. Which function equation represents this scenario.
3 answers
Joker has a workout when he trains for track. He warms up with a light jog for 2 miles at a constant rate for 16 minutes. Then he stretches for 5 minutes before running 5 miles at a constant rate for 20 minutes. Which function equation represents this scenario.
d=1/8m for t≤16 ; d=2 for t>16 but t≤21
d=1/8m for t<=16: d=2 for t > 16 but t<=21;
d=1/8m+20.75 for t>21<=41
d=1/8m for t<=16; d=2 for t > 16 but t<=21;
d=1/8m+3.25 for t>21<=41
d=1/8m for t≤16 ; d=2 for t>16 but t≤21
d=1/8m for t<=16: d=2 for t > 16 but t<=21;
d=1/8m+20.75 for t>21<=41
d=1/8m for t<=16; d=2 for t > 16 but t<=21;
d=1/8m+3.25 for t>21<=41
None of the provided equation options accurately represent the given scenario.
The correct function equation that represents this scenario is:
d = (1/8)m for t ≤ 16 ;
d = 2 for 16 < t ≤ 21 ;
d = (1/8)m + 3.25 for t > 21 ≤ 41
The correct function equation that represents this scenario is:
d = (1/8)m for t ≤ 16 ;
d = 2 for 16 < t ≤ 21 ;
d = (1/8)m + 3.25 for t > 21 ≤ 41