JOHN WANTS TO PADDLE HIS CANOE ACROSS A RIVER THAT IS 200M WIDE, HE STARTS FROM THE EAST SIDE. THE WATER CURRENT FLOWS NORTH-SOUTH AT 0.5MS^-1. IT TAKES JOHN 252S TO CROSS THE RIVER.

Question

1. DRAW A DIAGRAM TO GRAPHICALLY REPRESENT THE VELOCTY VECTORS OF THE WATER CANOE AND THEIR RESULTANT

2.CALCULATE THE DIRECTION JOHN HEADED HIS CNOE TO FOLLOW A COURSE DUE WEST ACROSS THE RIVER

Answer 1

He ends up going 200 meters west in 252 seconds.
Therefore we an figure out his west velocity component:
Vw = 200/252 m/s

Meanwhile he is carried south at .5 m/s so he will have to have a north component of
Vn = .5 m/s
So we can figure the angle north of west he has to head.

tan A = Vn/Vw

Head A degrees north of west and you go straight west :)