John is going to make a house purchase and borrow $300,000 and has two options. John can have a mortgage for 30 years and interest rate of 7.5% or a mortgage for 15 years at an interest rate of 7.25%. What is the interest rate written as a decimal for the 30 loan?

What was your equation to find the monthly payment for the 30 year loan.
Show how you find the total paid for the 30 year loan.
What was your equation to find the monthly payment for the 15 year loan?
How do you find the total paid for the 15 year loan?
How much money is saved if the minimum payment was paid for 15 years instead of the minimum payment for 30 years

1 answer

To address your questions step by step, we will calculate the interest rate as a decimal, find the monthly payments and total paid for both the 30-year and 15-year loans, and finally determine the savings from choosing the 15-year loan over the 30-year loan.

Step 1: Interest Rate as Decimal for the 30-Year Loan

The interest rate for the 30-year loan is 7.5%. As a decimal, this is calculated as:

\[ \text{Interest Rate} = \frac{7.5}{100} = 0.075 \]

Step 2: Monthly Payment for the 30-Year Loan

To calculate the monthly payment for a fixed-rate mortgage, we can use the formula:

\[ M = P \frac{r(1+r)^n}{(1+r)^n - 1} \]

Where:

  • \( M \) = monthly payment
  • \( P \) = loan principal ($300,000)
  • \( r \) = monthly interest rate (annual rate / 12)
  • \( n \) = total number of payments (loan term in months)

For the 30-year loan:

  • \( P = 300,000 \)
  • \( r = \frac{0.075}{12} = 0.00625 \)
  • \( n = 30 \times 12 = 360 \)

Plugging in these values:

\[ M = 300,000 \frac{0.00625(1 + 0.00625)^{360}}{(1 + 0.00625)^{360} - 1} \]

Calculating \( (1 + 0.00625)^{360} \):

\[ (1 + 0.00625)^{360} \approx 7.6136 \quad \text{(using a calculator)} \]

Now substitute back into the formula:

\[ M = 300,000 \frac{0.00625 \times 7.6136}{7.6136 - 1} \]

\[ M = 300,000 \frac{0.047604}{6.6136} \approx 300,000 \times 0.007196 \approx 2158.72 \]

Step 3: Total Paid for the 30-Year Loan

The total amount paid over the term of the loan is given by:

\[ \text{Total Paid} = M \times n \]

So for the 30-year loan:

\[ \text{Total Paid} = 2158.72 \times 360 \approx 776,155.20 \]

Step 4: Monthly Payment for the 15-Year Loan

Using the same formula for the 15-year loan with \( r = \frac{0.0725}{12} = \frac{0.0725}{12} = 0.00604167 \) and \( n = 15 \times 12 = 180 \):

\[ M = 300,000 \frac{0.00604167(1 + 0.00604167)^{180}}{(1 + 0.00604167)^{180} - 1} \]

Calculating \( (1 + 0.00604167)^{180} \):

\[ (1 + 0.00604167)^{180} \approx 2.8678 \quad \text{(using a calculator)} \]

Substituting:

\[ M = 300,000 \frac{0.00604167 \times 2.8678}{2.8678 - 1} \]

\[ M = 300,000 \frac{0.01729}{1.8678} \approx 300,000 \times 0.009252 \approx 2775.61 \]

Step 5: Total Paid for the 15-Year Loan

\[ \text{Total Paid} = M \times n = 2775.61 \times 180 \approx 500,193.80 \]

Step 6: Savings by Choosing 15-Year Loan Instead of 30-Year Loan

\[ \text{Savings} = \text{Total Paid (30 years)} - \text{Total Paid (15 years)} \]

Calculating: \[ \text{Savings} = 776,155.20 - 500,193.80 \approx 275,961.40 \]

Summary of Results

  • Interest Rate (30 years): 0.075
  • Monthly Payment (30 years): Approx. $2158.72
  • Total Paid (30 years): Approx. $776,155.20
  • Monthly Payment (15 years): Approx. $2775.61
  • Total Paid (15 years): Approx. $500,193.80
  • Savings by choosing 15-year loan: Approx. $275,961.40

These results help compare the two loan options effectively.