J = John present age
S = sister present age
J = S + 8
After 3 years John wil be J + 3 yrs old.
Sister wil be S + 3 yrs old.
In three years,he will be as twice as she will be then mean:
( J + 3 ) / ( S + 3 ) = 2
In this equation replace J with S + 8
( S + 8 + 3 ) / ( S + 3 ) = 2
( S + 11 ) / ( S + 3 ) = 2
Multiply both sides by S + 3
S + 11 = 2 ( S + 3 )
S + 11 = 2 S + 6
Subtract 6 to both sides
S + 11 - 6 = 2 S + 6 - 6
S + 5 = 2 S
Subtract S to both sides
S + 5 - S = 2 S - S
5 = S
S = 5
J = S + 8 = 5 + 8 = 13
John is 13 yrs old, sister is 5 yrs old.
Proof:
After 3 years John wil be 13 + 3 = 16 yrs old
Sister wil be 5 + 3 = 8 yrs old
16 / 8 = 2
John is eight year older than his sister.In three years,he will be as twice as she will be then.
How old are they both now?
2 answers
Sister: X yrs. old.
John: x + 8 yrs. old.
3 yrs. later:
Sister: x + 3.
John: (x+8) + 3 = x + 11.
x + 11 = 2(x + 3),
X = 5.
x + 8 = 5 + 8 = 13.
John: x + 8 yrs. old.
3 yrs. later:
Sister: x + 3.
John: (x+8) + 3 = x + 11.
x + 11 = 2(x + 3),
X = 5.
x + 8 = 5 + 8 = 13.