8 markers
3/8 times 2/7
since there is no replacement.. choosing from 7 and we have to assume that we got a red the first time which leaves 2 red.
John hs 3 red markers and 5 blue markers. What is the probability that he picks a red marker, and then, without replacing it, selects another red marker?
Please show me how to set this up (you don't have to give me the answer)...thank you
1 answer