To find the probability of John making all three free throws, we multiply the probability of making one free throw by itself three times:
P(making all three free throws) = (0.55)^3
P(making all three free throws) = 0.55 * 0.55 * 0.55
P(making all three free throws) = 0.166375
Therefore, the percent chance that John makes all three free throws is 16.6375%.
John has to make all 3 free throws to win the game. Assume each free throw is an independent event and that the pressure of the situation has no impact on him. If John is a 55% free throw shooter what is the percent chance that John makes all three free throws? Do not round your answer. (Click Here for Help Video)(10 points)
1 answer